Three equal electric charges of each charge ' $q$ ' are placed at the vertices of an equilateral triangle of…
- $\frac{1}{4 \pi \epsilon_0} \cdot \frac{3 q^2}{L}$
- $\frac{1}{4 \pi \epsilon_0} \cdot \frac{q^2}{3 L}$
- $\frac{1}{4 \pi \epsilon_0} \cdot \frac{2 q^2}{3 L}$
- $\frac{1}{4 \pi \epsilon_0} \cdot \frac{q^2}{L}$
Solution

The potential energy of the charge system is $\mathrm{U}=3\left(\frac{\mathrm{kq}}{\mathrm{~L}}\right)=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{3 \mathrm{q}^2}{\mathrm{~L}}$
Asked in: AP EAMCET 2024 (21 May Shift 1)