Three designs are proposed for an engine which is to operate between $500 \mathrm{~K}$ and $300 \mathrm{~K}$…

Three designs are proposed for an engine which is to operate between $500 \mathrm{~K}$ and $300 \mathrm{~K}$. Design A claims to produce $150 \mathrm{~J}$ of work per $1000 \mathrm{~J}$ of heat input, design $B 450 \mathrm{~J}$ of work per $1000 \mathrm{~J}$ and design $C 300 \mathrm{~J}$ of work per $1000 \mathrm{~J}$. Which of the design would you choose?
  1. A
  2. B
  3. C
  4. None is suitable

Solution

Given, temperature, $T_1=500 \mathrm{~K}, T_2=300 \mathrm{~K}$ Efficiency of the engine, $\eta=1-\frac{T_2}{T_1}$ $ \begin{array}{ll} \Rightarrow & \eta=1-\frac{300}{500} \\ \Rightarrow & \eta=\frac{2}{5}=0.4 \end{array} $ For design A, work done = 150 J Heat input = 1000 J $\begin{aligned} \text { Efficiency of design } A & =\frac{\text { Work done }}{\text { Heat input }} \\ & =\frac{150}{1000}=0.15\end{aligned}$ For design B, work done = 450 J Heat input = 1000 J $\begin{aligned} \text { Efficiency of design } B & =\frac{\text { Work done }}{\text { Heat input }} \\ & =\frac{450}{1000}=0.45\end{aligned}$ For design C, work done = 300 J Heat input = 1000 J Efficiency of design $\begin{aligned} C & =\frac{\text { Work done }}{\text { Heat input }} \\ & =\frac{300}{1000}=0.3\end{aligned}$ Hence, design B is most suitable as its efficiency is almost equal to efficiency of given engine

Asked in: AP EAMCET 2021 (25 Aug Shift 2)

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