Three concentric charged metallic spherical shells $A, B$ and $C$ have radii $a, b$ and $c$; charge…
- $V_{A}=(a+b+c) \frac{\sigma}{\varepsilon_{0}}$
- $V_{B}=\left(\frac{a^{2}}{b}-b+c\right) \frac{\sigma}{\varepsilon_{0}}$
- $V_{C}=\left(\frac{a^{2}+b^{2}}{b}+c\right) \frac{\sigma}{\varepsilon_{0}}$
- $V_{A}=V_{B}=V_{C}=(a+b+c) \frac{\sigma}{\varepsilon_{0}}$
Solution
(i) Potential of A
\(\begin{aligned}
& =(\text { Potential of A due to }+\sigma \text { on A }) \\
& +(\text { Potential of A due to }-\sigma \text { on B }) \\
& +(\text { Potential of A due to }+\sigma \text { on C }) \\
& =K\left[\frac{4 \pi \mathrm{a}^2 \sigma}{\mathrm{a}}-\frac{4 \pi \mathrm{b}^2 \sigma}{\mathrm{b}}+\frac{4 \pi \mathrm{c}^2 \sigma}{\mathrm{c}}\right] \\
& =\frac{\sigma}{\epsilon_0}[\mathrm{a}-\mathrm{b}+\mathrm{c}]
\end{aligned}\)
Potential of \(\mathrm{B}=(\) Potential due to \(+\sigma\) on \(\mathrm{A})+(\) Potential due to \(-\sigma\) on \(\mathrm{B})\)

\(\begin{aligned}
& +(\text { Potential due to }+\sigma \text { on } \mathrm{C}) \\
& =\mathrm{K}\left[\frac{4 \pi \mathrm{a}^2 \sigma}{\mathrm{a}}-\frac{4 \pi \mathrm{b}^2 \sigma}{\mathrm{b}}+\frac{4 \pi \mathrm{c}^2 \sigma}{\mathrm{c}}\right] \\
& =\frac{\sigma}{\epsilon_0}\left[\frac{\mathrm{a}^2}{\mathrm{~b}}-\mathrm{b}+\mathrm{c}\right]
\end{aligned}\)
Potential of \(\mathrm{C}=(\) Potential due to \(+\sigma\) on \(\mathrm{A})+(\) Potential due to \(-\sigma\) on \(\mathrm{B})+(\) Potential due to \(+\sigma\) on \(\mathrm{C}\) )
\(\begin{aligned}
& =K\left[\frac{4 \pi \mathrm{a}^2 \sigma}{\mathrm{a}}-\frac{4 \pi \mathrm{b}^2 \sigma}{\mathrm{b}}+\frac{4 \pi \mathrm{c}^2 \sigma}{\mathrm{c}}\right] \\
& =\frac{\sigma}{\epsilon_0}\left[\frac{\mathrm{a}^2}{\mathrm{~b}}-\frac{\mathrm{b}^2}{\mathrm{c}}+\mathrm{c}\right]
\end{aligned}\)
Asked in: JEE Mains - Electrostatics - Test 4