Three collinear points $P, Q, R$ with $PQ = 4$, $QR = 5$. If $Q$ is between $P$ and $R$, then $PR$ is

Three collinear points $P, Q, R$ with $PQ = 4$, $QR = 5$. If $Q$ is between $P$ and $R$, then $PR$ is
  1. $9$
  2. $1$
  3. $20$
  4. $-1$

Solution

$PR = PQ + QR = 9$.

Asked in: MH-SSC-9

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