Three coins are tossed. Probability of getting at least one Tail is:

Three coins are tossed. Probability of getting at least one Tail is:
  1. $\dfrac{1}{8}$
  2. $\dfrac{3}{8}$
  3. $\dfrac{7}{8}$
  4. $\dfrac{1}{2}$

Solution

$P(\text{no tail}) = P(HHH) = \dfrac{1}{8}$. $P(\text{at least one tail}) = 1 - \dfrac{1}{8} = \dfrac{7}{8}$.

Asked in: IMO

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