Three coins are tossed. Probability of getting all Heads is:
Three coins are tossed. Probability of getting all Heads is:
- $\dfrac{1}{2}$
- $\dfrac{1}{4}$
- $\dfrac{1}{8}$
- $\dfrac{3}{8}$
Solution
Total outcomes $= 2^{3} = 8$. Favourable $= \{HHH\}$. $P = \dfrac{1}{8}$.
Asked in: IMO
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