Three charges of each magnitude $100 \mu \mathrm{C}$ are placed at the corners $A, B$ and $C$ of an equilateral triangle of side $4 \mathrm{~m}$. If the charges at points $A$ and $C$ are positive and the charge at point $B$ is negative, then the magnitude of total force acting on the…

Question

Three charges of each magnitude $100 \mu \mathrm{C}$ are placed at the corners $A, B$ and $C$ of an equilateral triangle of side $4 \mathrm{~m}$. If the charges at points $A$ and $C$ are positive and the charge at point $B$ is negative, then the magnitude of total force acting on the charge at $C$ and angle made by it with $A C$ are

Aicharya · Accepted Answer

According to the question, we can draw the following diagram,

From the question, it clear that the charge on the each corner is $100 \mu \mathrm{C}$. So, $\begin{aligned} F_{\text {net }} & =F \\ & =\frac{k Q_1 Q_2}{r^2} \end{aligned}$ Given, $Q_1=Q_2=100 \mu \mathrm{C}=100 \times 10^{-6} \mathrm{C}, \quad\left[1 \mu \mathrm{C}=10^{-6} \mathrm{C}\right]$ and $r=4 \mathrm{~m}$ Putting the given values in Eq. (i), we get $\begin{aligned} & =\frac{9 \times 10^9 \times\left(100 \times 10^{-6}\right)^2}{(4)^2} \\ F_{\text {net }} & =5.625 \mathrm{~N}, 60^{\circ} \end{aligned}$

Three charges of each magnitude \(100 \mu \mathrm{C}\) are placed at the corners \(A, B\) and \(C\) of an…

Solution