Three charges each of value $+q$ are placed at the corners of an isosceles triangle $\mathrm{ABC}$ of sides…

Three charges each of value $+q$ are placed at the corners of an isosceles triangle $\mathrm{ABC}$ of sides $\mathrm{AB}$ and $\mathrm{AC}$ each equal to $2 \mathrm{a}$. The mid points of $A B$ and $A C$ are $D$ and $E$ respectively. The work done in taking a charge $\mathrm{Q}$ from $\mathrm{D}$ to $\mathrm{E}$ is $\left(\varepsilon_0=\right.$ permittivity of free space)
  1. Zero
  2. $\frac{3 \mathrm{qQ}}{4 \pi \varepsilon_0 \mathrm{a}}$
  3. $\frac{\mathrm{qQ}}{8 \pi \varepsilon_0 \mathrm{a}}$
  4. $\frac{3 \mathrm{qQ}}{8 \pi \varepsilon_0 \mathrm{a}}$

Solution

$\begin{aligned} & \text { Given } A B=A C=2 a \\ & V_D=V_E \quad(\because D \text { and } E \text { are mid-points }) \end{aligned}$ $\therefore \quad$ The work done in taking a charge $\mathrm{q}$ from $\mathrm{D}$ to $\mathrm{E}$ is $\begin{array}{rlrl} & W=q \Delta V=q\left(V_D-V_E\right) \\ \therefore \quad & W=0 & \text { (Equipotential surfaces) } \end{array}$

Asked in: MHT CET 2023 (13 May Shift 1)

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