
Three charges, each $+q$, are placed at the corners of an isosceles triangle $A B C$ of sides $B C$ and $A C…

- $\frac{e q Q}{8 \pi \varepsilon_0 a}$
- $\frac{q Q}{4 \pi \varepsilon_0 a}$
- zero
- $\frac{3 q Q}{4 \pi \varepsilon_0 a}$
Solution
$\begin{aligned}
& V_D=V_E=V \\
& W=Q\left[V_E-V_D\right] \\
& W=Q[V-V] \\
& W=0
\end{aligned}$
.Asked in: NEET 2011 (Mains)