Three capacitors each of 4   μ F are to be connected in such a way that the effective capacitance…

1. all in series
2. all in parallel
3. two in parallel and one in series
4. two in series and one in parallel

Solution

For top branch,

$\frac{1}{{\mathrm{C}}_{\mathrm{eq}}}=\frac{1}{4}+\frac{1}{4}$

$\Rightarrow {\mathrm{C}}_{\mathrm{eq}}=2\mathrm{ }\mathrm{\mu F}$

For parallel combination, ${\mathrm{C}}_{\mathrm{net}}=2+4=6\mathrm{ }\mathrm{\mu F}$

Asked in: JEE Main 2016 (09 Apr Online)

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