Three blocks of masses $2 \mathrm{~m}, 4 \mathrm{~m}$ and 6 m are placed as shown in figure. If $\sin 37^{\circ}=\frac{3}{5}, \sin 53^{\circ}=\frac{4}{5}$ the acceleration of the system is

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Aicharya · Accepted Answer

$\begin{aligned} & F_{n e t}=(2 m+4 m+6 m) a \\ \Rightarrow \quad & 10 \mathrm{mg} \sin 53^{\circ}-2 \mathrm{mg} \sin 37^{\circ}=12 \mathrm{ma}\end{aligned}$

$\begin{aligned} & \Rightarrow \mathrm{a}=\frac{\left(10 \times \frac{4}{5}-2 \times \frac{3}{5}\right) g}{12} \\ & \therefore \mathrm{a}=\frac{17}{30} \mathrm{~g}\end{aligned}$

Three blocks of masses $2 \mathrm{~m}, 4 \mathrm{~m}$ and 6 m are placed as shown in figure. If $\sin…

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