This equation represents the preparation of gold sol by $2 \mathrm{AuCl}_3+3 \mathrm{HCHO}+3 \mathrm{H}_2…

This equation represents the preparation of gold sol by $2 \mathrm{AuCl}_3+3 \mathrm{HCHO}+3 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{Au}+3 \mathrm{HCOOH}+6 \mathrm{HCl}$.
  1. Oxidation
  2. Reduction
  3. Double decomposition
  4. Hydrolysis

Solution

In the given reaction, gold $(\mathrm{Au})$ goes from +3 state in $\mathrm{AuCl}_3$ to zero in $\mathrm{Au}$. Thus, reduction is taking place in the preparation of Au sol.

Asked in: AP EAMCET 2023 (17 May Shift 2)

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