Thermal decomposition of $\mathrm{HCOOH}$ is a first order reaction and the rate constant at $T(K)$ is $4.606 imes 10^{-3} \mathrm{~s}^{-1}$. The time required to decompose $90 \%$ of initial quantity of $\mathrm{HCOOH}$ at $T(\mathrm{~K})$ in second is

Question

Thermal decomposition of $\mathrm{HCOOH}$ is a first order reaction and the rate constant at $T(K)$ is $4.606 	imes 10^{-3} \mathrm{~s}^{-1}$. The time required to decompose $90 \%$ of initial quantity of $\mathrm{HCOOH}$ at $T(\mathrm{~K})$ in second is

Aicharya · Accepted Answer

First order reaction $ \begin{aligned} & \qquad K=\frac{2.303}{t} \log \frac{A_0}{A} \ & 	ext { Given, } K=4.606 	imes 10^{-3} \mathrm{~s}^{-1} \ & A=90 \%, A_0=	ext { Initial quantity }=100 \% \ & t=\frac{2.303}{4.606 	imes 10^{-3}} \log \frac{1}{1-9} \ & t=500 \mathrm{~s} \end{aligned} $

Thermal decomposition of $\mathrm{HCOOH}$ is a first order reaction and the rate constant at $T(K)$ is $4…

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