There are two holes one each along the opposite sides of a wide rectangular tank. The cross-section of each…
There are two holes one each along the opposite sides of a wide rectangular tank. The cross-section of each hole is $0.01 \mathrm{~m}^2$ and the vertical distance between the holes is one metre. The tank is filled with water.The net force on the tank in newton when the water flows out of the holes is
(Density of water $=1000 \mathrm{~kg} / \mathrm{m}^3$ )
$100$
$200$
$300$
$400$
Solution
The net force on the tank
where $F=2 A \rho g h$
$A=$ area of cross-section of the hole
$\rho=$ density of water
$h=$ vertical distance between the holes
$\therefore F=2 \times 0.01 \times 1000 \times 10 \times 1$ $=200 \mathrm{~N}$