There are two balls in an urn. Each ball can be either white or black. If a white ball is put into the urn…

There are two balls in an urn. Each ball can be either white or black. If a white ball is put into the urn and there after a ball is drawn at random from the urn, then the probability that it is white is
  1. $\frac{1}{4}$
  2. $\frac{2}{3}$
  3. $\frac{1}{5}$
  4. $\frac{1}{3}$

Solution

Total possible event when one ball is taken out $={ }^3 \mathrm{C}_1$ Let $E$ : The event of 1 white ball coming out No. of ways to 1 white ball coming out $={ }^2 \mathrm{C}_1$ $ \therefore P(E)=\frac{{ }^2 C_1}{{ }^3 C_1}=\frac{2}{3} $

Asked in: JEE Main 2012 (26 May Online)

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