There are ten boys B 1 ,   B 2 , … . , B 10 and five girls G 1 , G 2 , … . G 5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B 1 and B 2 together should not be the members of a group, is _____.

Question

There are ten boys B 1 , &#160; B 2 , &#8230; . , B 10 and five girls G 1 , G 2 , &#8230; . G 5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B 1 and B 2 together should not be the members of a group, is _____.

Aicharya · Accepted Answer

Given, total number of boys is 10 and total number of girls is 5 So total number of selections = C 3 10 &#183; C 3 5 = 1200 No. of selections in which B 1 &#160; &#38; &#160; B 2 both are there in group = C 1 8 &#183; C 3 5 = 80 Required no. of selections = 1200 - 80 = 1120

There are ten boys B 1 ,   B 2 , … . , B 10 and five girls G 1 , G 2 , … . G 5 in a class.…

Solution

There are ten boys B 1 , &#160; B 2 , &#8230; . , B 10 and five girls G 1 , G 2 , &#8230; . G 5 in a class.…

Solution

There are ten boys B 1 , B 2 , … . , B 10 and five girls G 1 , G 2 , … . G 5 in a class.…