There are ' $n$ ' number of identical electric bulbs, each is designed to draw a power $p$ independently from the mains supply. They are now joined in series across the main supply. The total power drawn by the combination is :

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Aicharya · Accepted Answer

$\begin{aligned} & R_s=R_1+R_2+R_3+\ldots \ldots..+R_n \ & \frac{V^2}{P_s}=\frac{V^2}{P}+\frac{V^2}{P}+\ldots \ldots.+\frac{V^2}{P_n} \ & P_s=\frac{P}{n}\end{aligned}$

There are ' $n$ ' number of identical electric bulbs, each is designed to draw a power $p$ independently…

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