There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are…

There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are collinear. Then the total number of triangles that can be formed with the vertices at any three of these 12 points is
  1. 230
  2. 220
  3. 200
  4. 210

Solution

${ }^{12} \mathrm{C}_3-{ }^5 \mathrm{C}_3=210$ ,

Asked in: JEE Main 2025 (08 Apr Shift 2)

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