$3 \lambda \vec{c}+2 \mu(\vec{a} \times \vec{b})=0$ then

$3 \lambda \vec{c}+2 \mu(\vec{a} \times \vec{b})=0$ then
  1. $3 \lambda+2 \mu=0$
  2. $3 \lambda=2 \mu$
  3. $\lambda=\mu$
  4. $\lambda+\mu=0$

Solution

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Asked in: JEE Main 2002

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