The $x$ and $y$ coordinates of a particle at any time $t$ are given by $x=7 t+4 t^{2}$ and $y=5 t$, where $x$ and $y$ are in $\mathrm{m}$ and $t$ in s. The acceleration of the particle at $5 \mathrm{~s}$ is (in SI units)

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Aicharya · Accepted Answer

$a_{x}=\frac{d^{2} x}{d t^{2}}=8$ and $a_{y}=\frac{d^{2} y}{d t^{2}}=0$ Hence, net acceleration $=\sqrt{a_{x}^{2}+a_{y}^{2}}=8 \mathrm{~m} / \mathrm{s}^{2}$

The \(x\) and \(y\) coordinates of a particle at any time \(t\) are given by \(x=7 t+4 t^{2}\) and \(y=5 t\)…

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