The work done in blowing a soap bubble of radius 'R' is ' $\mathrm{W}$ '. The work done in blowing a bubble…

The work done in blowing a soap bubble of radius 'R' is ' $\mathrm{W}$ '. The work done in blowing a bubble of radius ' $2 \mathrm{R}^{\prime}$ of the same soap solution is
  1. $\frac{\mathrm{w}}{4}$
  2. $\frac{\mathrm{w}}{2}$
  3. 4w
  4. 2w

Solution

$\mathrm{W}_{1}=8 \pi \mathrm{R}^{2} \mathrm{~T}$ where $\mathrm{T}$ is surface tension. If radius is doubled and surface tension remains same then $\mathrm{W}_{2}=8 \pi(2 \mathrm{R})^{2} \mathrm{~T}=8 \pi \mathrm{R}^{2} \mathrm{~T}=4 \mathrm{~W}_{1}$ However, the solution is heated, the value of surface tension decreases. Hence, $\mathrm{W}_{2} < 4 \mathrm{~W}_{1}$

Asked in: MHT CET 2020 (16 Oct Shift 2)

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