The work done by a gas molecule in an isolated system is given by, W = α β 2 e - x 2 α k…

The work done by a gas molecule in an isolated system is given by, W=αβ2e-x2αk T, where x is the displacement, k is the Boltzmann constant and T is the temperature. α and β are constants. Then the dimensions of β will be:
  1. M2 L T2
  2. ML2 T-2
  3. MLT-2
  4. M0 L T0

Solution

x2αkT dimensionless

α=x2kT=L2ML2 T-2=M-1 T2

Now W=αβ2

β=ML2 T-2M-1 T2=M1 L1 T-2

Asked in: JEE Main 2021 (24 Feb Shift 1)

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