The work done by a Carnot engine operating between $300 \mathrm{~K}$ and $400 \mathrm{~K}$ is $400 \mathrm{~J}$. The energy exhausted by the engine is

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Aicharya · Accepted Answer

Given, source temperature, $T_1=400 \mathrm{~K}$ Sink temperature, $T_2=300 \mathrm{~K}$ Work done, $W=400 \mathrm{~J}$ We know that, efficiency of carnot heat engine $\eta=\frac{W}{Q}=1-\frac{T_2}{T_1}$ $\Rightarrow \quad \frac{W}{Q}=1-\frac{T_2}{T_1} \Rightarrow \frac{400}{Q}=1-\frac{300}{400}$ $\Rightarrow \quad \frac{400}{Q}=\frac{1}{4} \Rightarrow Q=1600 \mathrm{~J}$ $	herefore$ Energy exhausted by the heat engine $=Q-W$ $=1600-400=1200 \mathrm{~J}$

The work done by a Carnot engine operating between $300 \mathrm{~K}$ and $400 \mathrm{~K}$ is $400…

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