The wavelength of light absorbed for the following complexes are in the order…

The wavelength of light absorbed for the following complexes are in the order $\underset{\text{(I)}}{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}} ;\underset{\text{(II)}}{\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}} ;\underset{\text{(III)}}{\left[\mathrm{Co}(\mathrm{CN})_6\right]^{3-}} ;\underset{\text{(IV)}}{\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{H}_2 \mathrm{O}\right)\right]^{3+}} ;\underset{\text{(V)}}{\left[\mathrm{CoF}_6\right]^{3-}}$
  1. III $<$ I $<$ IV $<$ V $<$ II
  2. III $<$ I $<$ IV $<$ II $<$ V
  3. III $<$ I $<$ II $<$ IV $<$ V
  4. III $<$ IV $<$ I $<$ II $<$ V

Solution

Wavelength of light absorbed increases as C.F.S.E of complex decreases.
$[Co(CN)_6]^{3-}$ has maximum CFSE
$[CoF_6]^{3-}$ has least CFSE
Ligand field strength $\uparrow$ ; C.F.S.E $\uparrow$
Correct wavelength order.
$V > II > IV > I > III$

Asked in: JEE Main 2026 (24 Jan Shift 2)

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