The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat,…

The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat, $\left.\mathrm{R}=\frac{10^7}{\mathrm{~m}}\right)$
  1. $16 \times 10^4 \mathrm{~m}^{-1}$
  2. $8 \times 10^5 \mathrm{~m}^{-1}$
  3. $36 \times 10^7 \mathrm{~m}^{-1}$
  4. $25 \times 10^5 \mathrm{~m}^{-1}$

Solution

The wave number of the last line of the Balmer series is given by $\frac{1}{\lambda}=\frac{\mathrm{R}}{4}=\frac{10^7}{4}=25 \times 10^5 \mathrm{~m}^{-1}$ :

Asked in: MHT CET 2021 (21 Sep Shift 2)

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