The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat,…
The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat, $\left.\mathrm{R}=\frac{10^7}{\mathrm{~m}}\right)$
$16 \times 10^4 \mathrm{~m}^{-1}$
$8 \times 10^5 \mathrm{~m}^{-1}$
$36 \times 10^7 \mathrm{~m}^{-1}$
$25 \times 10^5 \mathrm{~m}^{-1}$
Solution
The wave number of the last line of the Balmer series is given by $\frac{1}{\lambda}=\frac{\mathrm{R}}{4}=\frac{10^7}{4}=25 \times 10^5 \mathrm{~m}^{-1}$
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