The wave number of first line in Lyman series of hydrogen atom is ( $R$ is Rydberg's constant)
The wave number of first line in Lyman series of hydrogen atom is ( $R$ is Rydberg's constant)
$\frac{3 R}{2}$
$\frac{3 R}{4}$
$2 R$
$\frac{R}{2}$
Solution
According to Rydberg equation:
$\frac{1}{\lambda}=R\left(1-\frac{1}{n^2}\right)$
For first line, electron moves from $n=2$ to the lowest energy level of the electron.
Therefore, corresponding wave no. is given by: $\frac{3 R}{4}$