The wave function of atomic orbital of H like species is given as
$ψ_{2 s} = \frac{1}{4 \sqrt{2} π} Z^{\frac{3}{2}} (2 - Z r) e^{- \frac{Z r}{2}}$
The radius for nodal surface for $H e^{+}$ ion in $Å$ .

Question

The wave function of atomic orbital of H like species is given as &#968; 2 s = 1 4 2 &#960; Z 3 2 2 - Z r e - Z r 2 The radius for nodal surface for H e + ion in &#197; .

Aicharya · Accepted Answer

As at nodal surface probability of finding an electron is zero, therefor, &#968; = 0 So 2 - Z r = 0 r = 2 Z = 2 2 = 1 &#8196; &#197; ^

The wave function of atomic orbital of H like species is given as ψ 2 s = 1 4 2 π Z 3 2 2 - Z r e…

Solution

The wave function of atomic orbital of H like species is given as &#968; 2 s = 1 4 2 &#960; Z 3 2 2 - Z r e…

Solution

The wave function of atomic orbital of H like species is given as ψ 2 s = 1 4 2 π Z 3 2 2 - Z r e…