The wave described by $y=0.25 \sin (10 \pi x-2 \pi t)$, where $\mathrm{x}$ and $\mathrm{y}$ are in meters…
The wave described by $y=0.25 \sin (10 \pi x-2 \pi t)$, where $\mathrm{x}$ and $\mathrm{y}$ are in meters and $\mathrm{t}$ in seconds, is a wave travelling along the
-ve $\mathrm{x}$ direction with amplitude $0.25 \mathrm{~m}$ and wavelength $\lambda=0.2 \mathrm{~m}$
-ve $x$ direction with frequency $1 \mathrm{~Hz}$
+ve $\mathrm{x}$ direction with frequency $\pi \mathrm{Hz}$ and wavelength $\lambda=0.2 \mathrm{~m}$
+ve $\mathrm{x}$ direction with frequency $1 \mathrm{~Hz}$ and wavelength $\lambda=0.2 \mathrm{~m}$
Solution
Give, $y=0.25 \sin (10 \pi x-2 \pi t)$
Comparing with $y=A \sin \left(\frac{2 \pi}{\lambda} \cdot x-2 \pi n t\right)$, we get,
$\begin{aligned}
& \lambda=0.2 \mathrm{~m} \\
& n=1 \mathrm{~Hz}
\end{aligned}$
-ve sign indicates, the $x$ direction.
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