The volume strength of $1.5 \mathrm{~N} \mathrm{H}_{2} \mathrm{O}_{2}$ solution is

The volume strength of $1.5 \mathrm{~N} \mathrm{H}_{2} \mathrm{O}_{2}$ solution is
  1. $4.8$
  2. $8.4$
  3. $3.0$
  4. $8.0$

Solution

Normality of 10 volume $\mathrm{H}_{2} \mathrm{O}_{2}=1.78 \mathrm{~N}$
Thus, volume strength of $1.78 \mathrm{~N}$ solution $=10$
$\therefore$ Volume strength of
$1.5 \mathrm{~N} \mathrm{H}_{2} \mathrm{O}_{2}=1.5 \times \frac{10}{1.78}=\frac{15}{1.78}=8.4$ *

Asked in: JEE-TOPICTESTS-CHEMISTRY

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