The volume strength (in $\mathrm{L}$ ) of $3 \mathrm{NH}_2 \mathrm{O}_2$ is approximately

The volume strength (in $\mathrm{L}$ ) of $3 \mathrm{NH}_2 \mathrm{O}_2$ is approximately
  1. $3$
  2. $8$
  3. $17$
  4. $9$

Solution

$3 \mathrm{~N}$ means 3 equivalent weight in $1 \mathrm{~L}$ solution, $N=\frac{\text { Weight }}{\text { Equivalent weight }}$ Equivalent weight for $\mathrm{H}_2 \mathrm{O}_2=17 \mathrm{~g}$ $\therefore \quad 3=\frac{\text { Weight }}{17}$ Weight $=3 \times 17=51 \mathrm{~g}$ $\mathrm{H}_2 \mathrm{O}_2 \longrightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2$ We know that, $68 \mathrm{~g}$ of $\mathrm{H}_2 \mathrm{O}_2$ gives $22.4 \mathrm{~L}$ of oxygen. $\therefore 51 \mathrm{~g}$ of $\mathrm{H}_2 \mathrm{O}_2$ will give $=22.4 \times \frac{51}{68}$ of oxygen $=16.8 \approx 17$

Asked in: AP EAMCET 2021 (24 Aug Shift 2)

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