The volume ratio of 6N and 2N HCl required to prepare 100 mL of 5N HCl is

The volume ratio of 6N and 2N HCl required to prepare 100 mL of 5N HCl is
  1. 3 : 1
  2. 1 : 3
  3. 4 : 1
  4. 1 : 4

Solution

Let a mL of 6N and 100−a  mL of 2N are mixed
So 6a+2(100-a)=100×5
a = 75 mL, 100−1  = 25 mL ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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