The volume of parallelopiped formed by vectors $\hat{i}+m \hat{j}+\hat{k}, \hat{j}+m \hat{k}$ and $m…
- 2
- 3
- $\sqrt{3}$
- $\frac{1}{\sqrt{3}}$
Solution
For max. or $\min$. of $V, \frac{d V}{d m}=0$ $\therefore \quad \mathrm{m}^2=\frac{1}{3}$ $\therefore \quad \mathrm{m}=\frac{1}{\sqrt{3}}$ $\frac{d^2 V}{d m^2}=6 m\gt0$ for $m=\frac{1}{\sqrt{3}}$ $\therefore \quad \mathrm{V}$ is minimum for $\mathrm{m}=\frac{1}{\sqrt{3}}$
Asked in: MHT CET 2024 (02 May Shift 1)