The volume of HCl , containing 73 g   L - 1 , required to completely neutralise NaOH obtained by reacting 0 . 69   g of metallic sodium with water, is _____ mL . (Nearest Integer) (Given : molar Masses of Na , Cl , O , H are 23 , 35 . 5 , 16 and 1 g   mol - 1 respectively)

Question

The volume of HCl , containing 73 g &#160; L - 1 , required to completely neutralise NaOH obtained by reacting 0 . 69 &#160; g of metallic sodium with water, is _____ mL . (Nearest Integer) (Given : molar Masses of Na , Cl , O , H are 23 , 35 . 5 , 16 and 1 g &#160; mol - 1 respectively)

Aicharya · Accepted Answer

Mole of NaOH = 0 . 69 23 = 3 &#215; 10 - 2 2 Na + 2 H 2 O &#10230; 2 NaOH + H 2 Number of moles of Na = Number of moles of NaOH NaOH &#160; + &#160; HCl &#160; &#8594; &#160; NaCl &#160; + &#160; H 2 O Moles of HCl = moles of NaOH &#8658; &#160; ( Molarity &#160; &#215; &#160; V ) HCl &#160; = &#160; Number of moles of NaOH &#8658; &#160; 73 36 . 5 &#160; &#215; &#160; 1 &#160; &#215; &#160; V &#160; = &#160; 0 . 03 &#8658; V &#160; = &#160; 15 &#160; &#215; &#160; 10 - 3 &#160; Lit &#8658; &#160; V &#160; = &#160; 15 &#160; mL

The volume of HCl , containing 73 g   L - 1 , required to completely neutralise NaOH obtained by…

Solution

The volume of HCl , containing 73 g &#160; L - 1 , required to completely neutralise NaOH obtained by…

Solution

The volume of HCl , containing 73 g L - 1 , required to completely neutralise NaOH obtained by…