The volume of an ideal gas contracts from 10.0 L to 2.0 L under an applied pressure of 2.0 atm . During…

The volume of an ideal gas contracts from 10.0 L to 2.0 L under an applied pressure of 2.0 atm . During contraction the system also evolved 900 J of heat. The change in internal energy (in J) involved in the system is ( 1 L atm $\left.=101.3^{\prime} \mathrm{J}\right)$
  1. $720.8$
  2. $360.4$
  3. $1620.8$
  4. $810.4$

Solution

Given, $\begin{aligned} & \text { Heat released }=-900 \mathrm{~J} \\ & \begin{array}{l} \Delta \mathrm{u}=\mathrm{q}+\mathrm{w} \\ =-900 \mathrm{~J}+(-2 \mathrm{~atm}(2-10) \mathrm{L}) \\ =-900 \mathrm{~J}+16 \mathrm{Latm} \\ =-900 \mathrm{~J}+16 \times 101.35 \mathrm{~J} \\ =721.6 \mathrm{~J} \end{array} \end{aligned}$

Asked in: AP EAMCET 2024 (20 May Shift 2)

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