The vibrations of a string of length $60 ext{ cm}$ fixed at both ends are represented by the equation $y = 4 \sin \left(\frac{\pi x}{15} ight) \cos (96\pi t)$, where $x$ and $y$ are in cm and $t$ in second. The maximum displacement at $x = 5 ext{ cm}$ is

Question

The vibrations of a string of length $60	ext{ cm}$ fixed at both ends are represented by the equation $y = 4 \sin \left(\frac{\pi x}{15}ight) \cos (96\pi t)$, where $x$ and $y$ are in cm and $t$ in second. The maximum displacement at $x = 5	ext{ cm}$ is

Aicharya · Accepted Answer

$A_x = 4 \sin \left( \frac{\pi x}{15} ight)$ At $x = 5	ext{ cm}$, $A_x = 4 \sin \frac{\pi}{3} = 2\sqrt{3}	ext{ cm}$

The vibrations of a string of length $60\text{ cm}$ fixed at both ends are represented by the equation $y =…

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