The velocity ( v ) and time ( t ) graph of a body in a straight line motion is shown in the figure. The point S is at 4 . 333 seconds. The total distance covered by the body in 6   s is :

Question

The velocity ( v ) and time ( t ) graph of a body in a straight line motion is shown in the figure. The point S is at 4 . 333 seconds. The total distance covered by the body in 6 &#160; s is :

Aicharya · Accepted Answer

Total distance covered by the body is equal to the modulus of area under graph velocity-time graph

$\Rightarrow d = (\frac{1}{2} \times 4 \times 2) + (4 \times 1) + (\frac{1}{2} \times 4 \times \frac{4}{3}) + (\frac{1}{2} \times 2 \times \frac{5}{3})$

$\Rightarrow d = 4 + 4 + \frac{8}{3} + \frac{5}{3}$

$\Rightarrow d = \frac{37}{3} m$

The velocity ( v ) and time ( t ) graph of a body in a straight line motion is shown in the figure. The…

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