
The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance…

- $30\mathrm{~m}$
- $11\mathrm{~m}$
- $10\mathrm{~m}$
- $13\mathrm{~m}$
Solution
$\begin{aligned} \Rightarrow \text { Distance } & =\text { Area } \\ & =\frac{1}{2}(2 \mathrm{~s}+4 \mathrm{~s})(10 \mathrm{~m} / \mathrm{s}) \\ & =30 \mathrm{~m}\end{aligned}$
Asked in: JEE Main 2025 (28 Jan Shift 2)