The velocity-time graph of a particle of mass 10   kg is shown in the figure. The net work done on the…

The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is

  1. -9300 J
  2. 12000 J
  3. -4500 J
  4. -12000 J

Solution

v=-5t+50

vt=2=40


Work done= K.E. =12402-502×10

=-4500J

Asked in: JEE Main 2016 (10 Apr Online)

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