
The velocity-time graph of a body is shown in fig. The ratio of average acceleration during the intervals $O…

- 1
- $\frac{1}{2}$
- $\frac{1}{3}$
- 3
Solution
During $\mathrm{AB}$, acceleration $=-\tan 60^{\circ}$ $=-\sqrt{3} \mathrm{~m} / \mathrm{s}^{2}$
Required ratio $=\frac{1 / \sqrt{3}}{\sqrt{3}}=\frac{1}{3}$
Asked in: JEE Mains - Motion In One Dimension - Test 3