The velocity of sound through a diatomic gaseous medium of molecular weight $M$ at $0^\circ\text{C}$, is
The velocity of sound through a diatomic gaseous medium of molecular weight $M$ at $0^\circ\text{C}$, is
$\sqrt{\frac{R}{M}}$
$\sqrt{\frac{3R}{M}}$
$\sqrt{\frac{382R}{M}}$
$\sqrt{\frac{273 R}{M}}$
Solution
Velocity of sound through gaseous medium, $v = \sqrt{\frac{\gamma RT}{M}}$.
For diatomic gas, $\gamma = 1.4$ and $T = 273\text{ K}$
$\cdot\cdot\cdot\text{ }\gamma T \approx 382$
$\cdot\cdot\cdot$ The velocity of sound through a diatomic gaseous medium,
$v = \sqrt{\frac{382 R}{M}}$