The velocity of a projectile at the initial point $A$ is $(2 \mathbf{i}+3 \mathbf{j}) \mathrm{m} /…
The velocity of a projectile at the initial point $A$ is $(2 \mathbf{i}+3 \mathbf{j}) \mathrm{m} / \mathrm{s}$. Its velocity (in $\mathrm{m} / \mathrm{s}$ ) at point $B$ is
$-2 \mathbf{i}-3 \mathbf{j}$
$-2 \mathbf{i}+3 \mathbf{j}$
$2 \mathbf{i}-3 \mathbf{j}$
$2 \mathbf{i}+3 \mathbf{j}$
Solution
From the figure the $X$-component remain unchanged, while the $Y$-component is reverse. Then, the velocity at point $B$ is $(2 \mathrm{i}-3 \mathrm{j}) \mathrm{ms}^{-1}$.
