The velocity of a particle which starts from rest is given by the following table.
The total distance travelled (in metre) by the particles in $10 \mathrm{~s}$, using Trapezoidal rule is given by

Question

The velocity of a particle which starts from rest is given by the following table. The total distance travelled (in metre) by the particles in $10 \mathrm{~s}$, using Trapezoidal rule is given by

Aicharya · Accepted Answer

Given table is

Here, $\quad h=\frac{10-0}{5}=2$ $\begin{aligned} & \therefore \text { Total distance }=\frac{h}{2}\left[f\left(x_0\right)+2\left\{f\left(x_1\right)+f\left(x_2\right)\right.\right. \\ & \left.\left.+f\left(x_3\right)+f\left(x_4\right)\right\}+f\left(x_5\right)\right] \\ & =\frac{2}{2}[0+2(12+16+20+35)+60] \\ & =166+60=226 \\ & \end{aligned}$

The velocity of a particle which starts from rest is given by the following table. The total distance…

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