The velocity of a particle is $\mathrm{v}=\mathrm{v}_0+\mathrm{gt}+\mathrm{ft}^2$. If its position is…
The velocity of a particle is $\mathrm{v}=\mathrm{v}_0+\mathrm{gt}+\mathrm{ft}^2$. If its position is $\mathrm{x}=0$ at $\mathrm{t}=0$, then its displacement after unit time $(t=1)$ is
$\mathrm{v_0+2 g+3 f}$
$\mathrm{v_0+g / 2+f / 3}$
$\mathrm{v_0+g+f}$
$\mathrm{v_0+g / 2+f}$
Solution
$\mathrm{\int_0^x d x=\int_0^1\left(V_0+g t+\mathrm{ft}^2\right) d t}$
$\mathrm{x=v_0+g\left(\frac{1}{2}\right)+f\left(\frac{1}{3}\right)}$