The velocity of a particle is given by the, equation $v(x)$ $=3 x^2-4 x$, where ' $x$ ' is the distance covered by the particle. The expression for its acceleration is

Question

Aicharya · Accepted Answer

Velocity, $v=3 x^2-4 x$ $	herefore \quad$ Acceleration, $a=v \cdot \frac{d v}{d x}=\left(3 x^2-4 xight) \frac{d}{d x}\left(3 x^2-4 xight)$ $=\left(3 x^2-4 xight)(6 x-4)$

The velocity of a particle is given by the, equation $v(x)$ $=3 x^2-4 x$, where ' $x$ ' is the distance…

Solution