The velocity of a particle is given by $v=2 t^2-8 t+15 \mathrm{~ms}^{-1}$. Find its instantaneous…
The velocity of a particle is given by $v=2 t^2-8 t+15 \mathrm{~ms}^{-1}$. Find its instantaneous acceleration at $t=5 \mathrm{~s}$.
- $18 \mathrm{~ms}^{-2}$
- $20 \mathrm{~ms}^{-2}$
- $5 \mathrm{~ms}^{-2}$
- $12 \mathrm{~ms}^{-2}$
Solution
Given, velocity, $v=2 t^2-8 t+15$
$
\text { time, } t=5 \mathrm{~s}
$
Let acceleration be $a$.
$
\begin{aligned}
\because \quad & a=\frac{d v}{d t} \\
\therefore \quad & a=4 t-\left.8\right|_{t=5} \\
& =4 \times 5-8 \\
& =20-8 \\
& =12 \mathrm{~ms}^{-2}
\end{aligned}
$
Asked in: AP EAMCET 2021 (23 Aug Shift 1)
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