The vectors 3 a → - 5 b → and 2 a → + b → are mutually perpendicular and the vectors a → + 4 b → and - a → +…

The vectors 3a-5b and 2a+b are mutually perpendicular and the vectors a+4b and -a+b are also mutually perpendicular. Then the angle between the vectors a and b, is
  1. cos-119543
  2. π-cos-119543
  3. cos-19543
  4. π-cos-19543

Solution

   (3a-5b)(2a+b)=0

   ab=6a2-5b27 ...(i)

and (a+4b)(b-a)=0

 ab=4b2-a23 ...(ii)

From equation (i) and (ii),

a=4325b  and  ab=abcosθ

 cosθ=19b24325 b2=19543

Asked in: MHT CET Full Test 5

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