The vector projection of $\overline{P Q}$ on $\overline{A B}$, where $P \equiv(-2,1,3), Q \equiv(3,2,5), A…

The vector projection of $\overline{P Q}$ on $\overline{A B}$, where $P \equiv(-2,1,3), Q \equiv(3,2,5), A \equiv(4,-3,5)$ and $B \equiv(7,-5,-1)$ is
  1. $\frac{1}{49}(3 \hat{i}-2 \hat{j}-6 \hat{k})$
  2. $\frac{1}{7}(3 \hat{i}-2 \hat{j}+6 \hat{k})$
  3. $(3 \hat{i}-2 \hat{j}-6 \hat{k})$
  4. $\frac{1}{7}(3 \hat{i}-2 \hat{j}-6 \hat{k})$

Solution

$\begin{aligned} & \overline{P Q}=(3+2) \hat{i}+(2-1) \hat{j}+(5-3) \hat{k}=5 \hat{i}+\hat{j}+2 \widehat{k} \\ & \overline{A B}=(7-4) \hat{i}+(-5+3) \hat{j}+(-1-5) \hat{k}=3 \hat{i}-2 \hat{j}-6 \hat{k} \end{aligned}$ now vector projection of $\overrightarrow{P Q}$ on $\overrightarrow{A B}$ is $\frac{(\overrightarrow{P Q} \cdot \overrightarrow{A B}) \overrightarrow{A B}}{|\overrightarrow{A B}|^2}$ $=\frac{\{5 \times 3+1 \times(-1)+2 \times(-6)\}(3 \hat{i}-2 \hat{j}-6 \hat{k})}{3^2+(-2)^2+(-6)^2}=\frac{1}{49}(3 \hat{i}-2 \hat{j}-6 \hat{k})$

Asked in: MHT CET 2022 (11 Aug Shift 1)

Practice more Vectors questions on Aicharya