The variation of velocity of a particle moving along a straight line is shown in Fig. The distance travelled…

The variation of velocity of a particle moving along a straight line is shown in Fig. The distance travelled by the particle in \(12 \mathrm{~s}\) is
  1. \(37.5 \mathrm{~m}\)
  2. \(32.5 \mathrm{~m}\)
  3. \(35.0 \mathrm{~m}\)
  4. None of these.

Solution

Area from 0 to \(10 s=\frac{1}{2}[10+4] \times 5=35 \mathrm{~m}\)
Area from 10 to \(12 \mathrm{~s}=\frac{1}{2} \times 2 \times(-2.5)=-2.5 \mathrm{~m}\)
Distance travelled \(=35+2.5=37.5 \mathrm{~m}\)

Asked in: JEE Mains - Motion In One Dimension - Chapter Test

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