The vapour pressure of pure benzene and toluene at a particular temperature are $100 \mathrm{~mm}$ and $50…
- $0.67$
- $0.75$
- $0.33$
- $0.50$
Solution
$=100+50=150 \mathrm{~mm}$
We know, $\mathrm{P}_{\mathrm{C}_{6} \mathrm{H}_{6}}^{\mathrm{o}}=\mathrm{P} \times \mathrm{X}_{\mathrm{C} 6 \mathrm{H} 6}$
$100=150 \times \mathrm{X}_{\mathrm{C} 6 \mathrm{H} 6}$
$X_{C 6 H 6}=\frac{100}{150}=0.67$
Asked in: JEE-TOPICTESTS-CHEMISTRY