The vapour pressure of pure benzene and methyl benzene at \(27^{\circ} \mathrm{C}\) is given as 80 Torr and…

The vapour pressure of pure benzene and methyl benzene at \(27^{\circ} \mathrm{C}\) is given as 80 Torr and 24 Torr, respectively. The mole fraction of methyl benzene in vapour phase, in equilibrium with an equimolar mixture of those two liquids (ideal solution) at the same temperature is _______ \(\times 10^{-2}\) (nearest integer)

Solution

$\begin{aligned} \mathrm{X}_{\text {methylbenzene }} & =0.5 \\ \mathrm{Y}_{\text {methylbenzene }} & =\frac{\mathrm{P}_{\text {methylbenzene }}}{\mathrm{P}_{\text {total }}} \\ \mathrm{Y}_{\text {methylbenzene }} & =\frac{0.5 \times 24}{0.5 \times 80+0.5 \times 24} \\ & =\frac{12}{40+12}=0.23=23 \times 10^{-2}\end{aligned}$

Asked in: JEE Main 2024 (09 Apr Shift 2)

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